866 字
4 分钟
[C#] Range函数, 好用就完事儿了!
这么多重载, 完全够用了~, 返回值是 IEnumerable<T> 其中, Range函数是简单的循环, RangeEx加入了检测, 不会造成死循环, 且精度非常准确
using System;using System.Collections.Generic;
namespace NullLib.Range{ public class NRange { public static IEnumerable<int> Range(int stop) { for (int i = 0; i < stop; i++) yield return i; } public static IEnumerable<int> Range(int start, int stop) { for (int i = start; i < stop; i++) yield return i; } public static IEnumerable<int> Range(int start, int stop, int step) { for (int i = start; i < stop; i += step) yield return i; } public static IEnumerable<float> Range(float stop) { for (int i = 0; i < stop; i++) yield return i; } public static IEnumerable<float> Range(float start, float stop) { for (float i = start; i < stop; i++) yield return i; } public static IEnumerable<float> Range(float start, float stop, float step) { for (float i = start; i < stop; i += step) yield return i; } public static IEnumerable<double> Range(double stop) { for (int i = 0; i < stop; i++) yield return i; } public static IEnumerable<double> Range(double start, double stop) { for (double i = start; i < stop; i++) yield return i; } public static IEnumerable<double> Range(double start, double stop, double step) { for (double i = start; i < stop; i += step) yield return i; } public static IEnumerable<int> RangeEx(int stop) { int start = 0, step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<int> RangeEx(int start, int stop) { int step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<int> RangeEx(int start, int stop, int step) { int current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<float> RangeEx(float stop) { float start = 0, step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<float> RangeEx(float start, float stop) { float step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<float> RangeEx(float start, float stop, float step) { float current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<double> RangeEx(double stop) { double start = 0, step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<double> RangeEx(double start, double stop) { double step = 1, current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } public static IEnumerable<double> RangeEx(double start, double stop, double step) { double current = start; step = step < 0 ? -step : step; if (start < stop) for (int i = 0; current < stop; i++, current = step * i + start) yield return current; else for (int i = 0; current > stop; i--, current = step * i + start) yield return current; } }} [C#] Range函数, 好用就完事儿了!
https://slimenull.com/posts/20210219070741/